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PROJECT: BARON REAL ESTATE DATE:
PROJ. NO.: 29603-1 ENGINEER:
CLIENT: SIGN STORE COMPANY
V5.5 units; pounds, feet unless noted otherwise
Applied Wind Loads; from ASCE 7-16
F=qz*G*Cf*Af with qz = 0.00256KzKztKdV2 (29.3.2 & 29.4)
Cf=1.483 (Fig. 29.3-1)1.00 0 max. height= 8.00
1.0 Kzt=1.0 (26.8.2) (=1.0 unless unusual landscape)s= 7.67
Kz=from table 28.3-1 Exposure= c 2
Kd=0.85 for signs (table 26.6-1)
Lz=
V= 160 mph
G= 0.85 (26.9)weight= 0.698 kips
s/h=0.958 MDL=0.00 k-ft
B/s=1.17
Pole structure height at Wind
Loads component section c.g.
Kz qz Af shear Moment MW
1 3.8 0.850 47.3 69.0 4118 15788
2 7.8335 0.850 47.3 0.7 45 350
sums: 69.8 4163 16.14
(Mw)k-ft arm= 3.9
for s/h=1, add 10% (asce fig. 29.4-1):x 1.10 17.75
Pu=0.84 kip M= 17.75 k-ft
M=sqrt(MDL
2+Mw
2)
Mu=sqrt(1.2MDL
2+1.0MW
2) =17.75 k-ft
Pole Design section; pipe
Mu < φMn with Mn = fyZfy=35 ksi ࢥ=0.9
H Mu(k-ft)t (in) Z USE
at grade 17.8 0.258 6.8 PIPE 6 STD, ĭMn= 27.8 k-ft
Z req'd. (in) Size(in)
6.76 5
59.68
4/13/21
MAF
pressure
qz*G*Cf
59.68
10815 Rancho Bernardo RD., SD, CA 92127
projectmanager@sullawayeng.com
Phone: 858-312-5150 Fax: 858-777-3534
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PROJECT: BARON REAL ESTATE DATE:
PROJ. NO.: 29603-1 ENGINEER:
CLIENT: SIGN STORE COMPANY
Version 3.0 Longitude Direction units; pounds, feet unless noted otherwise
applied shear at grade v=2.5 kip unfactored load
applied moment at grade m=9.68 kip-ft unfactored load
depth of soil above footing hs=0 ft
allowable soil bearing p=2.0 ksf
Spread Footing Design
moment m= 15.9 k-ft at base of footing
Footing size (ft) b=10.00 L=4.0 h=2.50 S= 26.7
Footing Weight= 15.0 k signage weight=0.7 k soil 0.00 total= 15.70
Overturning;Mc=31 Mc>1.5M 1.9713 ok
soil pressure; max= 1.062 ksf min= -0.2 ksf ok
forces on concrete pad; V= 13.8 k
Vr=22 k (=1.6V)
M=14 k-ft Mr=22 k-ft
Check Slab;
ࢥ=0.9 fy=60 ksi
fc=2.5 ksi 150 lbs/ft3
Flexure As=0.25 d= 26.0 in
φMn=φAsfy(d-a/2)=351 k-in = 29.2 k-ft Mr<φMn ok
a=Asfy/0.85fcb= 0.059 in
Check minimum Asmin=2sqrt(fc)bd/fy =7.8 200bd/fy=10.40 or 1.333As=0.33 in2
Use As=0.33in2
short direction γs=2/(β+1) =0.8 with
β=1.5 short direction;
γAs=0.27 in2
USE #4 @ 12" Each Way Top and Bottom Mat
Shear;φVn=φ2sqrt(fc)bd φVc=ࢥ=0.75 Vr<φVn ok
4/20/21
MAF
234.0
P.O. Box 28789, SD, CA 92198
mikesullaway@gmail.com
Phone: 858-312-5150 Fax: 858-777-3534
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