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DESIGN OF HAPCO ALUMINUM LIGHTING POLES
CATALOG No. 33777-0725
PROJECT: ISLAND BEACH RESORT
St Lucie County, Florida.
DESIGN CRITERIA: FLORIDA BUILDING CODE 2020
170 MPH (max with Gust) Using ASCE7-16, Per Section 1601 & 1819
Date: 10-18-2020
References:
ASCE 7-10 & 7-16 — Minimum Design Loads for Buildings & Other Structures
Florida Building Code 2020 Chapter 16 for Structures and 18 for Foundations Cat.I
AASHTO Standard Specifications for Highway Signs, Luminaries and Traffic Signals
1994 & 2014
FDOT Standard Specifications
Catalog Cut Sheets
Prepared By: James E. Wild, P.E.
592 Lancaster Gate SE
North Canton Ohio 44709
Submitted By: Precision Outdoor Lighting, Inc.
3832 Shipping Ave
Miami, F1 33146
Submitted by Power & Liqhtinq Systems, Inc. Catalog Number: Type:
a Job Name: 33777-0725-01 (32' OAH) SATIN
Island Beach Resort ALUMINUM FINISH
Notes: 25FT MH 321FT OA RTA DIRECT BURIED POLE
SINGLE DRILL FOR ACUITY DSXO
FBC 2017, Ultimate Design Strength
Wind Speed With EPA Ratings(sq. ft_)
Item No. Hapco Part No A B C Weight
120
130
140
150
160
170
180
RTA2OC7BD 33777-0720 26' 20' 6' 210 lbs.
17.3
14.4
12.2
10.5
RTA25C78D 33777-0725 32 25 7 140 lbs.
1 i.6
9.4
7.9
6.7
5.7
4.9
4.3
The EPA Is Calculated At 1 ' above the shaft, and offset by 1 '-6"
For different loading cases, please contact Hopco.
B"
+I Mounting
Height
7" O.D. --
2'-0"
Flattened
References:
SKKPO60410A
30155
—Alum. Pole Cap With
S.S. Screws
Drilling Specified By Customer
SATIN FINISH
Internal Damper
(Factory Installed)
Tapered Alum. Tube
/ 156" Wall Alloy 6063—T6
Satin Ground ! <nish
Frame Tapped 3/8'-16NC For Grounding ` 3
4" x 6" Reinforced Handhole With
Cover And Stainless Steel Hex. Hd. Screws
Ground Line �gNgt�tl�a8/Nl ®g
F No A1383 �
1j" X 6" Long Slotted
Wire Hole (2 @ 180)
F3 112"
C t WARNING: DO NOT INSTALL LIGHTING POLES WITHOUT LUMINAIRES
DRE —20' & 25' EMBEDDED POLE
6.18 hapco MSIDMER
smE NTS DATE 6.14-18
er BAD Dwc. No.
Abingdon, Va. 33777
CHK'D
Submitted On: May 4, 2021 1/1 Index Page
POLE ID 33777-0725
By:
J.Wild, PE ver 10-1-12
(32' OAH, 25' MH)
Date:
10/18/2021
Project: Island Beach Resort
General Data:
Calculations: ASCII 7-16 & 2020 FiBC
C.G of Fixture
25 ft
q = 0.000256 *VA 2 = 73.984 psf
Base Height Above Ground
0 fit
Wind Pressure = 0.00256*Kz*Kzt*Kd*v"2
C.G of Fixture from Pole CL
2 ft
P =
7&93 psf
EPA, of Fixture (total)
0.95 sf
Fixtures:
Weight of Fixture (total)
17 lbs
Dead Load
17 lbs
Wind Speed (V)
170 mph
Wind Load
73.08 lbs
OT Moment
1827.04 ft-lbs
Material for Pole & Arm
Alum 6063
Pole Data:
Pole:
Shape of Pole
Rd
Dead Load:
123.64 lbs
Embedment Depth
7 ft
EPA
5.39 sf
Length
32 ft
Wind Load:
414.69 lbs
Base OD
7 in
C.G. of Pole
12.50 ft
Top OD
4.5 in
OT Moment
5183 62 ft-lbs
Wall Thickness
0.156 in
Torsion M
146.16 ft-lbs
Aver Unit Wt /LF
3.86 lbs/If
Area Aver_
2.74 in"2
Sum of loads Base:
r = (OD-t)/2 aver
2.80 in
axial
140.64 lbs
r = (od@base-t)/2 @ base
3A2 in
shear
487.77 lbs
Area @ Base
3.35 in
moment
7010.66 ft-lbs
Section Modulus @ Base
5.74 in"3
torsion
146.16 ft-lbs
Mom of Inertia @ Base
19.63 in"4
Torsion Constant (J)
11.47 in"4
Projected Area of Pole
11.98 sf
Exposure category
C
Kz for Pole:
0.95
Cf for Pole:
0.45
Kzt - use 1.0
1.00
Kd
1
Overload factor =
1.33
Stress Calculations:
Allowable Stresses:
Pole: fa = axial / Area =
42.0 psi
Fa = Fcylny =
17,727 psi
fib = OT Mom f Sect Mod.
= 14666.5 psi_
Fb = 1.17*Fty/1.65 =
17,727 psi
fv = (2*shear/a)+(torsion/j)
=
443.9 psi
or Fb = 124*Ftull.95 =
19,077 psi
CSR's:
use use
17,727 psi
Post: CSR = falFa + (fb/Fb)+(fvlFv
)A 2 =
0.62
Fv = Fsy/ny =
13,473 psi
csr <
1.0 so OK!
Check Embedment Depth of Pole:
REF FBC Table 1806.2 & Equation 1807.3.2.1
d= 0.5A.(1+(1+(4.36h/A))A1/2
Where Tabluated Value of Lateral Pressure (LP) = 100.00 psf
A = 2.34P/(S1 b), where S1 = 2`S*d/3, S1 = 466.67 psf
d= Depth of Embedment in fleet 7.00 ft
b = Diann of Post, Concrete or compacted fill 1.00 ft - average flatenned
(see 1806.3.3 - Increase for depth - increase tabulated value per foot of depth)
(see 1806.3.4 - Increase for Poles - Lateral Bearing Pressure two times table value)
(load that produces GrdLine Mom) P = Maximum Lateral Load 280.43 lbs - load that produces GrdLine Mom)
(assume load at fixture height) h = Dist from Load to Groundline 25 ft - assume load at fixture height
SOLVE for A = 2.34P/(S1 b) = 1.41
so
d= 0.5A(1+(1+(4.36h1A))^112) = ft
Embedment Depth Shown > Calculated so OK